SOLUTION: Given points A (-4,5) and B (6,-9), find the value of "n" so that point C (n,2) is equidistant from points A and B.

Algebra ->  Length-and-distance -> SOLUTION: Given points A (-4,5) and B (6,-9), find the value of "n" so that point C (n,2) is equidistant from points A and B.       Log On


   

Question 980904: Given points A (-4,5) and B (6,-9), find the value of "n" so that point C (n,2) is equidistant from points A and B.
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
AC=CB

The Distance Formula:
sqrt%28%28-4-c%29%5E2%2B%285-2%29%5E2%29=sqrt%28%286-n%29%5E2%2B%28-9-2%29%5E2%29
Simplify this and solve for c.

Answer by MathTherapy(10553) About Me  (Show Source):
You can put this solution on YOUR website!

Given points A (-4,5) and B (6,-9), find the value of "n" so that point C (n,2) is equidistant from points A and B. 
highlight_green%28n+=+6.6%29