SOLUTION: Hi! What is the simplified answer for this The index of both square rt is 5 Sqrt( x^4y^6) x sqrt(x^6y^12) And please do explain how Thank you very much :)

Algebra ->  Square-cubic-other-roots -> SOLUTION: Hi! What is the simplified answer for this The index of both square rt is 5 Sqrt( x^4y^6) x sqrt(x^6y^12) And please do explain how Thank you very much :)      Log On


   

Question 980803: Hi!
What is the simplified answer for this
The index of both square rt is 5
Sqrt( x^4y^6) x sqrt(x^6y^12)
And please do explain how
Thank you very much :)
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
What is the simplified answer for this
The index of both square rt is 5
Sqrt( x^4y^6) x sqrt(x^6y^12)
=======================
It's not a square root with an index.
It's a 5th root.
---
5throot( x^4y^6) x 5throot(x^6y^12)
Don't use x for multiply, use * (Shift 8)
x is used for other things.
root%285%2Cx%5E4y%5E6%29%2Aroot%285%2Cx%5E6y%5E12%29
The indices are the same, 5, so multiply
= root%285%2Cx%5E4y%5E6%2Ax%5E6y%5E12%29
Add exponents when multiplying
= root%285%2Cx%5E10y%5E18%29
= root%285%2Cx%5E10y%5E15%2Ay%5E3%29
= root%285%2Cx%5E10y%5E15%29%2Aroot%285%2Cy%5E3%29
= x%5E2y%5E3%2Aroot%285%2Cy%5E3%29