SOLUTION: I do not understand how to start working it out. Here is the question: 6x+20=10+3x+x

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Question 980567: I do not understand how to start working it out. Here is the question: 6x+20=10+3x+x
Found 3 solutions by macston, josgarithmetic, Boreal:
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
.
6x+20=10+3x+x
6x+20=10+4x Subtract 20+4x from each side
2x=-10 Divide each side by 2
x=-5

Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
You want all terms of x on one side of the equation.
Simplify;
Use multiplicative inverse for the coefficient on x and the multiplication property of equality.

6x%2B20-3x-x=10%2B3x%2Bx-3x-x, which used also the addition property of equality for the additive inverses of some terms of x;

Combining some steps...

2x=-10

highlight%28x=-5%29

Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
6x+20=10+3x+x
6x+20=10 +4x ;;;3x+1x=4x (x=1x)
subtract 4x from each side
6x-4x+20=10;;4x-4x;; 4x-4x=0
2x+20=10 ;; now the x's are on one side
subtract 20 from each side.
2x+20-20=10-20
2x=-10;; divide both sides by 2, not by 2x
2x/2=x
-10/2=-5
x= -5
Check
6(-5)+20=10 +3(-5)-5
-30+20=10-15-5
-10=-10
check