SOLUTION: Perimeter of a rectangular park is 300 feet. the length of the park is 50 feet longer than the width. find the length of the park

Algebra ->  Equations -> SOLUTION: Perimeter of a rectangular park is 300 feet. the length of the park is 50 feet longer than the width. find the length of the park       Log On


   

Question 980536: Perimeter of a rectangular park is 300 feet. the length of the park is 50 feet longer than the width. find the length of the park
Found 2 solutions by algebrahouse.com, Cromlix:
Answer by algebrahouse.com(1659) About Me  (Show Source):
You can put this solution on YOUR website!
w = width
w + 50 = length

Perimeter of a rectangle = 2(width) + 2(length)

2w + 2(w + 50) = 300 {substituted width and length into perimeter formula}
2w + 2w + 100 = 300 {used distributive property}
4w + 100 = 300 {combined like terms}
4w = 200 {subtracted 100 from each side}
w = 50 {divided each side by 4}

width = 50
length = 100

To ask a question, visit: www.algebrahouse.com

Answer by Cromlix(4381) About Me  (Show Source):
You can put this solution on YOUR website!
Hi there,
Make the width = 'x'
Width = x
Length = x + 50
Perimeter = 2 x Length + 2 x Width
300 = 2(x + 50) + (2(x))
300 = 2x + 100 + 2x
Collect like terms
2x + 2x = 300 - 100
4x = 200
x = 50
Width = 50 feet
Length = 100 feet.
Hope this helps:-)