SOLUTION: Find 3 consecutive integers such that the sum of one-half of the smallest and one-third of the largest is one less than the other integer?

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Question 980455: Find 3 consecutive integers such that the sum of one-half of the smallest and one-third of the largest is one less than the other integer?
Answer by onlinepsa(22) About Me  (Show Source):
You can put this solution on YOUR website!
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Let the 3 consecutive integers be (a-1), a and (a+1).

1/2 (a-1) + 1/3 (a+1) = a - 1
3a - 3 + 2a + 2= 6a -6
a= 5
The 3 consecutive integers be 4, 5 and 6.

Thanks,
PRD
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