On Monday a store put out 10 watermelons to be sold
So we start with 10 watermelons on Monday morning.
and some were sold.
Suppose x watermelons were sold.
So on Monday evening there were 10-x watermelons remaining.
on Tuesday the number leftover was doubled
So on Tuesday morning, there were 2(10-x) watermelons.
and again the same number were sold as on Monday.
So on Tuesday evening there were 2(10-x)-x watermelons remaining.
on Wednesday the number leftover was tripled
So on wednesday morning there were 3[2(10-x)-x] watermelons.
and the same sold as on Monday
So on Wednesday evening there were 3[2(10-x)-x]-x remaining.
leaving none left over.
So 3[2(10-x)-x]-x = 0
how many were sold each day ?
Solve that for x. I'll let you do that.
Edwin
