Question 980429: a father is four times as old as the son now.if the sum of their ages ten years ago was 60,find their present ages. Answer by Bibin(2) (Show Source):
You can put this solution on YOUR website! Here 10 years ago sum of ages 60. There for now thier sum of ages equals 60+10+10 = 80
Ratio of their ages = 4:1
Age of father = 80×4/5 =64
Age of son = 80×1/5 =16