SOLUTION: Given the function y = 3 sin 2pi x. a. Find the amplitude. b. Find the period.

Algebra ->  Trigonometry-basics -> SOLUTION: Given the function y = 3 sin 2pi x. a. Find the amplitude. b. Find the period.      Log On


   

Question 980243: Given the function y = 3 sin 2pi x. a. Find the amplitude. b. Find the period.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
y+=+3%2Asin%282pi%2Ax%29 is in the form y+=+A%2Asin%28B%2Ax%29 where |A| is the amplitude and 2pi%2FB is the period.

A = 3 ----> |A| = |3| = 3 is the amplitude

B+=+2pi, so 2pi%2FB+=+%282pi%29%2F%282pi%29+=+1 is the period

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Amplitude = 3

Period = 1