SOLUTION: Tickets in a raffle were 50c each, or you could buy five for $2. All 1000 tickets were sold and $470 was taken.How many lots of five tickets were solved?

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Tickets in a raffle were 50c each, or you could buy five for $2. All 1000 tickets were sold and $470 was taken.How many lots of five tickets were solved?       Log On


   

Question 980158: Tickets in a raffle were 50c each, or you could buy five for $2. All 1000 tickets were sold and $470 was taken.How many lots of five tickets were solved?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +a+ = number of single tickets sold
Let +b+ = number of lots of 5 tickets sold
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(1) +a+%2B+5b+=+1000+
(2) +50a+%2B+200b+=+47000+ ( in cents )
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(2) +a+%2B+4b+=+940+
Subtract (2) from (1)
(1) +a+%2B+5b+=+1000+
(2) +-a+-+4b+=+-940+
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+b+=+60+
and
(2) +a+%2B+4%2A60+=+940+
(2) +a+=+940+-+240+
(2) +a+=+700+
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60 lots of 5 tickets each were sold
check:
(2) +a+%2B+4b+=+940+
(2) +700+%2B+4%2A60+=+940+
(2) +700+%2B+240+=+940+
(2) +940+=+940+
OK