SOLUTION: e^2x-5e^x+4=0 x=? x=?

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Question 979793: e^2x-5e^x+4=0
x=?
x=?
Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
You might be trying to express e%5E%282x%29-5e%5Ex%2B4=0.

A temporary substitution of p=e%5Ex gives you p%5E2-5p%2B4=0.
%28p-4%29%28p-1%29=0

p=4 or p=1

Those values mean
either e%5Ex=4 OR e%5Ex=1.

Solution finally is highlight%28x=ln%284%29%29 or highlight%28x=0%29.