SOLUTION: find an equation of the ellipse having a major axis of length 12 and foci at (1,2) and (-3,2)

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Question 979639: find an equation of the ellipse having a major axis of length 12 and foci at (1,2) and (-3,2)
Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
find an equation of the ellipse having a major axis of length 12 and foci at
(1,2) and (-3,2)
We plot the foci (1,2) and (-3,2). 

Then we plot the center which is the midpoint between the two foci,
which is (-1,2). Then we draw the major axis 12 units long,
with the center at the middle, which means that we draw it 6 units 
on each side of the focus (in green).  That means that the vertices are 
(-7,2) and (5,2). 



We know that this ellipse looks like this:drawing%2820%2C10%2C-2%2C2%2C-1%2C1%2Carc%280%2C0%2C-3.9%2C1.9%29+%29.

Therefore its equation is 

%28x-h%29%5E2%2Fa%5E2%2B%28y-k%29%5E2%2Fb%5E2=1

The center is (h,k) = (-1,2).
We know that "a" = half the major axis = half of 12 = 6

So we can fill in h,k, and a:

%28x%2B1%29%5E2%2F6%5E2%2B%28y-2%29%5E2%2Fb%5E2=1

%28x%2B1%29%5E2%2F36%2B%28y-2%29%5E2%2Fb%5E2=1
We only need b, the semi-minor axis:



We calculate b from c%5E2=a%5E2-b%5E2
                    2%5E2=6%5E2-b%5E2
                    4=36-b%5E2
                    b%5E2=32
                    b=sqrt%2832%29
                    b=sqrt%2816%2A2%29
                    b=4sqrt%282%29, approximately 5.7 units
                    up and down from the center. 

So the equation is 

%28x%2B1%29%5E2%2F36%2B%28y-2%29%5E2%2F32=1  
                   
It looks like a circle but I'll draw a circle (in red) so you
can see that it's not quite a circle:


 
Edwin