SOLUTION: "An object is launched vertically in the air from a 10-meter tall platform. The height (in meters) of the object t seconds after it was launched is modeled by the function: h(t)=-1
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Question 979611: "An object is launched vertically in the air from a 10-meter tall platform. The height (in meters) of the object t seconds after it was launched is modeled by the function: h(t)=-16t^2+36t+10. How long will it take for the object to reach its maximum height? what is the maximum height?
a) the t-coordinate of the vertex is given by t=-b/2a= _______
b). the object reaches it maximum height ___ seconds after launch.
a). h(1.125)=_____
b) the maximum height of the object is ____ meters.
any help with this would be appreciated thank you so much Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! An object is launched vertically in the air from a 10-meter tall platform. The height (in meters) of the object t seconds after it was launched is modeled by the function: h(t)=-16t^2+36t+10. How long will it take for the object to reach its maximum height? what is the maximum height?
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h(t)=-16t^2+36t+10 is used on Earth for the height in feet (not meters).
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a) the t-coordinate of the vertex is given by t=-b/2a= _
It's -b/2a. Sub for b and a from the quadratic.
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b). the object reaches it maximum height ___ seconds after launch.
At the vertex, at t = -b/2a.
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a). h(1.125)=_____
Sub 1.125 for t in h(t)=-16t^2+36t+10
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b) the maximum height of the object is ____ meters.
It's not clear if it's meters or feet, but look at b above (the 1st b).
