Question 979547: A Swimming pool can be filled 15 hrs if water enters through a pipe alone, or in 23 hours if water enters through a hose a lone. if water entering through both the pipe and the hose, how long will it take to fill the pool 3/5 full?
x/15+x/23=3/5
(23x+15x)/23(15)=3/5
38x/345=3/5
im stuck here
Found 3 solutions by josgarithmetic, josmiceli, MathTherapy: Answer by josgarithmetic(39620) (Show Source):
You can put this solution on YOUR website! DELIVERY______________RATE(pool's-worth per hour)
Pipe__________________1/15
Hose__________________1/23
Pipe&Hose___________1/15+1/23
Uniform Rates Rule for task, job, work:
RT=V, to relate rate, time, amount of volume or space, meaning here, amount of pool capacity. You can say V=1 for one whole pool.
You can focus on doing the fill for pool, and let x be the amount of time in hours to do the amount of job.
You want to calculate x for both openings being used at the same time.

A bit of arithmetic; solve for x.
You seem to have the correct equation. YOU FORGOT TO MULTIPLY BOTH SIDES BY THE LOWEST COMMON DENOMINATOR.
Answer by josmiceli(19441) (Show Source): Answer by MathTherapy(10552) (Show Source):
You can put this solution on YOUR website!
A Swimming pool can be filled 15 hrs if water enters through a pipe alone, or in 23 hours if water enters through a hose a lone. if water entering through both the pipe and the hose, how long will it take to fill the pool 3/5 full?
x/15+x/23=3/5
(23x+15x)/23(15)=3/5
38x/345=3/5
im stuck here
You're right on track!! 
Just cross-multiply to get: 190x = 1,035
You should be able to complete this now!!
|
|
|