SOLUTION: A father is twice as old as his son. He was 6 times his son’s age 20 years ago. What is the father’s present age?

Algebra ->  Customizable Word Problem Solvers  -> Age -> SOLUTION: A father is twice as old as his son. He was 6 times his son’s age 20 years ago. What is the father’s present age?       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 979494: A father is twice as old as his son. He was 6 times his son’s age 20 years ago. What is the father’s present age?
Found 2 solutions by Boreal, Alan3354:
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
son's age now=x
father's age now=2x
[2x-20/x-20]=6
2x-20=6x-120, multiplying both sides by (x-20), and distributing 6 over that.
Then subtract 2x from both sides and add 120 to both sides.
4x=100
x=25
Son is 25
Father is 50 ANSWER.
20 years ago, father was 30, son was 5.

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
A father is twice as old as his son. He was 6 times his son’s age 20 years ago. What is the father’s present age?
-------------
F = 2S
F-20 = 6*(S-20)
Solve for F