SOLUTION: A jeweler wishes to prepare 200 grams of 80% pure gold from sources that are 68% pure gold and 83% pure gold how many grams of each should he use?

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Question 979472: A jeweler wishes to prepare 200 grams of 80% pure gold from sources that are 68% pure gold and 83% pure gold how many grams of each should he use?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +a+ = grams of 68% gold to be used
Let +b+ = grams of 83% gold to be used
--------------------------
(1) +%28+.68a+%2B+.83b+%29+%2F+200+=+.8+
(2) +a+%2B+b+=+200+
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(1) +.68a+%2B+.83+=+160+
(1) +68a+%2B+83b+=+16000+
Multiply both sides of (2) by +68+
and subtract (2) from (1)
(1) +68a+%2B+83b+=+16000+
(2) +-68a+-+68b+=+13600+
---------------------------
+15b+=+2400+
+b+=+160+
and
(2) +a+%2B+b+=+200+
(2) +a+=+40+
40 grams of 68% gold is to be used
160 grams of 83% gold is to be used
-----------------------------------
check:
(1) +%28+.68a+%2B+.83b+%29+%2F+200+=+.8+
(1) +%28+.68%2A40+%2B+.83%2A160+%29+%2F+200+=+.8+
(1) +%28+27.2+%2B+132.8+%29+%2F+200+=+.8+
(1) +160+=+.8%2A200+
(1) +160+=+160+
OK