SOLUTION: If {{{ (tan^3(x) - 1)/ (tan(x) - 1) - sec^2 (x) + 1 = 0 }}} find cot(x). Unable to solve this trig identity would appreciate help.

Algebra ->  Trigonometry-basics -> SOLUTION: If {{{ (tan^3(x) - 1)/ (tan(x) - 1) - sec^2 (x) + 1 = 0 }}} find cot(x). Unable to solve this trig identity would appreciate help.      Log On


   



Question 979423: If +%28tan%5E3%28x%29+-+1%29%2F+%28tan%28x%29+-+1%29+-+sec%5E2+%28x%29+%2B+1+=+0+ find cot(x).
Unable to solve this trig identity would appreciate help.

Answer by Edwin McCravy(20059) About Me  (Show Source):
You can put this solution on YOUR website!
+%28tan%5E3%28x%29+-+1%29%2F+%28tan%28x%29+-+1%29+-+sec%5E2%28x%29+%2B+1+=+0+

Factor the numerator as the difference of cubes: A%5E3-B%5E3=%28A-B%29%28A%5E2%2BAB%2BB%5E2%29

Since the denominator tan(x)-1 cannot be 0, tan(x) cannot be 1, so x
cannot be pi%2F4%2B2pi%2An or 5pi%2F4%2B2pi%2An



+tan%5E2%28x%29+%2Btan%28x%29+%2B+1+-+sec%5E2%28x%29+%2B+1+=+0+

+tan%5E2%28x%29+%2Btan%28x%29+-+sec%5E2%28x%29+%2B+2+=+0+

+tan%5E2%28x%29+%2Btan%28x%29+-+sec%5E2%28x%29+%2B+2+=+0+

Now we use the identity 1%2Btan%5E2%28theta%29=sec%5E2%28theta%29 solved for
                        tan%5E2%28theta%29=sec%5E2%28theta%29-1

+%28sec%5E2%28x%29-1%29+%2Btan%28x%29+-+sec%5E2%28x%29+%2B+2+=+0+

+sec%5E2%28x%29-1+%2Btan%28x%29+-+sec%5E2%28x%29+%2B+2+=+0+

tan%28x%29%2B1=0

tan%28x%29=-1

x=+3pi%2F4%2B2pi%2An or x+=+7pi%2F4%2B2pi%2An

x=+3pi%2F4%2B8pi%2An%2F4 or x+=+7pi%2F4%2B8pi%2An%2F4

x=+%283pi%2B8pi%2An%29%2F4 or x+=+%287pi%2B8pi%2An%29%2F4

x=+pi%283%2B8n%29%2F4 or x+=+pi%287%2B8n%29%2F4

Edwin