SOLUTION: A car uses 4 gallons of gasoline on a trip of 56 miles. At that rate, how much gasoline will a trip of 112 miles require?

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: A car uses 4 gallons of gasoline on a trip of 56 miles. At that rate, how much gasoline will a trip of 112 miles require?      Log On


   

Question 97935: A car uses 4 gallons of gasoline on a trip of 56 miles. At that rate, how much gasoline will a trip of 112 miles require?
Found 2 solutions by checkley71, anjali_yamini:
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
56/4=112/X CROSS MULTIPLY
56X=4*112
56X=448
X=8 GALLONS OF GAS WILL BE REQUIRED TO GO 112 MILES.
PROOF
56/4=112/8 CROSS MULTIPLY
56*8=112*4
448=448

Answer by anjali_yamini(27) About Me  (Show Source):
You can put this solution on YOUR website!

for 56 miles, the amount of gasoline required = 4 gallons
so, for 1 mile, the amount of gasoline required = 4/56 gallons
so, for 112 miles, the amount of gasoline required = (4/56) * 112
= (1/14)*112
= 8 gallons