SOLUTION: Find two consecutive positive integers such that the square of the second integer added to 5 times the first is equal to 121

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Question 979333: Find two consecutive positive integers such that the square of the second integer added to 5 times the first is equal to 121
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
first integer is x
second is (x+1)
5x+(x+1)^2=121
5x+x^2+2x+1=121
5x+x^2+2x=120
x^2+7x-120=0
(x+15)(x-8)=0
x=-15, +8
Want only positive integers
8 and 9
square of second is 81
5 times the first is 40
They add to 121