SOLUTION: The length of the line segment whose endpoints are (3,2) and (-2,1) is ?

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Question 979242: The length of the line segment whose endpoints are (3,2) and (-2,1) is ?
Found 2 solutions by ikleyn, Boreal:
Answer by ikleyn(52803) About Me  (Show Source):
You can put this solution on YOUR website!

This problem is very simple.

The  x-component of the line segment connecting the points  (3,2)  and  (-2,1)  is
dx = (-2) - 3 = -5.

The  y-component of this line segment is
1 - 2 = -1.

Now,  the length of this line segment is
sqrt%28dx%5E2+%2B+dy%5E2%29 = sqrt%28%28-5%29%5E2+%2B+%28-1%29%5E2%29 = sqrt%2825+%2B+1%29 = sqrt%2826%29 = 5.099 (approximately).


Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
Distance formula is sqrt[(difference in x)^2+(difference in y^2)]..You may go in either order so long as you square each, add the squares together and take the square root.
It is sqrt [(1-2)^2 + (-2-(3)^2]= sqrt (1+25)=SQRT (26)