SOLUTION: Please help me with this question!!! I would also like o thank you in advance for all your time and efforts put into solving this problem!! A woman jogging at 6mi/h passes a man

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Question 97910This question is from textbook Prentice Hall Pre- Algebra
: Please help me with this question!!! I would also like o thank you in advance for all your time and efforts put into solving this problem!!
A woman jogging at 6mi/h passes a man biking in the opposite direction at 12mi/h. If they maintain their speeds, how far from each other will they be in 10 min after passing?
Thank you, Thank you, THANK YOU!! This question is from textbook Prentice Hall Pre- Algebra

Found 2 solutions by aaaaaaaa, mathslover:
Answer by aaaaaaaa(138) About Me  (Show Source):
You can put this solution on YOUR website!
Uhm...
Woman -> 6mi%2Fh = cross%286%29mi%2Fcross%2860%29min = 1mi%2F10min
Bikeman -> 12mi%2Fh = cross%2812%29mi%2Fcross%2860%29min = 1mi%2F5min = 2mi%2F10min
In 10 minutes the woman will have walked 1 mile, while the bikerman will have walked 2 miles. As they're walking in opposite directions, they'll be three miles apart.

Answer by mathslover(157) About Me  (Show Source):
You can put this solution on YOUR website!
Distance covered by the woman in 10 minutes =speed* time
=6 * 10/60 (since 10 minutes = 10/60 hr)
= 1 mile

Distance covered by the man in 10 minutes = 12* 10/60
= 2mile
therefore they are (1+2) = 3miles apart after 10 minutes