SOLUTION: " If m varies directly as the square root of y, inversely as p^2, and inversely as n, what happens when y is quadrupled, p is tripped, and n is multiplied by two? A. m is multipl

Algebra ->  Expressions-with-variables -> SOLUTION: " If m varies directly as the square root of y, inversely as p^2, and inversely as n, what happens when y is quadrupled, p is tripped, and n is multiplied by two? A. m is multipl      Log On


   

Question 979083: "
If m varies directly as the square root of y, inversely as p^2, and inversely as n, what happens when y is quadrupled, p is tripped, and n is multiplied by two?
A. m is multiplied by 9
B. m is multipled by (1/9)
c. m remains the same
d. m is divided by (a/9)
"
This is what I have tried:
m=k+sqrt%28y%29
m=k%2Fp%5E2
m=+k%2Fn
If k (the constant of variation) is constant for all the variables, then
m=k+sqrt%28y%29%2Fp%5E2n
If you do the requested doubling and suchlike:
m=k+%282sqrt%28y%29%29%2F%283p%5E2%29%282n%29
If you multiply it by its inverse, I think it simplifies to something like:
2%2F3%2A2=2%2F6
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
m%5B1%5D=%28k%2Asqrt%28y%29%29%2F%28p%5E2%2An%29
m%5B2%5D=%28k%2Asqrt%284y%29%29%2F%28%283p%29%5E2%2A%282n%29%29
m%5B2%5D=%282k%2Asqrt%28y%29%29%2F%2818p%5E2%2An%29
m%5B2%5D=%281%2F9%29%28%28k%2Asqrt%28y%29%29%2F%28p%5E2%2An%29%29
m%5B2%5D=%281%2F9%29m%5B1%5D
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.
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You were almost there but you didn't square the 3 when you tripled p,
That would give you
2%2F%289%2A2%29=1%2F9