SOLUTION: A man flies a small airplane from Fargo to Bismarck, North Dakota --- a distance of 180 miles. Because he is flying into a head wind, the trip takes him 2 hours. On the way back, t

Algebra ->  Matrices-and-determiminant -> SOLUTION: A man flies a small airplane from Fargo to Bismarck, North Dakota --- a distance of 180 miles. Because he is flying into a head wind, the trip takes him 2 hours. On the way back, t      Log On


   

Question 978778: A man flies a small airplane from Fargo to Bismarck, North Dakota --- a distance of 180 miles. Because he is flying into a head wind, the trip takes him 2 hours. On the way back, the wind is still blowing at the same speed, so the return trip takes only 1 hour 12 minutes. What is his speed in still air, and how fast is the wind blowing?

Your answer is
his speed equals
the wind speed equals
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
r*t=d
with the wind
(r+w)*1.2=180
(r+w)=180/1.2
r+w=150.0
against the wind
(r-w)*2=180
(r-w)=180/2
r-w=90
r+w=150.0
add
r+r=150.0+90
2r=240.0
r=120.0 mph rate
120-w=90
w=120-90
w=30 mph wind
check
(120+30)*1.2=180
150*1.2=180
180.0=180
ok
(r-w)*2=180
(120-30)*2=180
90*2=180
180=180
ok
codedrtdtt