SOLUTION: Find the monic quadratic in the form {{{ x^2 + bx + c = 0 }}} with solutions {{{ x = 2+-sqrt ( 3 ) }}} Please show working

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Find the monic quadratic in the form {{{ x^2 + bx + c = 0 }}} with solutions {{{ x = 2+-sqrt ( 3 ) }}} Please show working      Log On


   

Question 978432: Find the monic quadratic in the form +x%5E2+%2B+bx+%2B+c+=+0+ with solutions
+x+=+2%2B-sqrt+%28+3+%29+
Please show working
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
+x+=+2%2B-sqrt+%28+3+%29+
+x-2+=+%22%22%2B-sqrt+%28+3+%29+
+%28x-2%29%5E2+=+%28%22%22%2B-sqrt+%28+3+%29%29%5E2+
+%28x-2%29%5E2+=+3+
+%28x-2%29%5E2+-+3+=+0+
+x%5E2+-+4x+%2B+4+-+3+=+0+
+x%5E2+-+4x+%2B+1+=+0+
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The answer is +x%5E2+-+4x+%2B+1+=+0+

If you compare +x%5E2+-+4x+%2B+1+=+0+ to +x%5E2+%2B+bx+%2B+c+=+0+, you will find that b+=+-4 and c+=+1