SOLUTION: the perimetre of a rectangle is 'h'm more than the sum of the length of its diagonals .If the area of the rectangle is 48sq.m,find the length and breadth of the rectangle.

Algebra ->  Rectangles -> SOLUTION: the perimetre of a rectangle is 'h'm more than the sum of the length of its diagonals .If the area of the rectangle is 48sq.m,find the length and breadth of the rectangle.       Log On


   

Question 978046: the perimetre of a rectangle is 'h'm more than the sum of the length of its diagonals .If the area of the rectangle is 48sq.m,find the length and breadth of the rectangle.
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
h meters more than ....

p , perimeter,
d, diagonal
w, L width and length

system%28p=2w%2B2L=h%2B2d%2CwL=48%29

More too.
w%5E2%2BL%5E2=d%5E2

Put the whole system together.
system%282w%2B2L=h%2B2d%2Cw%5E2%2BL%5E2=d%5E2%2CwL=48%29
which is three equations in three unknown variables.

The best way to continue is for YOU to decide what pathway to use to solve the system of equations. One way could be to try to use the first two equations in the system to eliminate d, and then work with a system of two equations in just w and L.
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Understand that you will only find solution formulas in terms of h, without any final value, because you are really NOT given enough information about h. You have actually three equations in FOUR unknown variables. h is simply an unknown constant.