SOLUTION: Hi, I need help!!!! I'm confused with these two questions and don't know where to begin. CV

Algebra ->  Linear-equations -> SOLUTION: Hi, I need help!!!! I'm confused with these two questions and don't know where to begin. CV       Log On


   



Question 977950: Hi, I need help!!!! I'm confused with these two questions and don't know where to begin.
CV

Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
5x + 3y = 7
y - 4 > 0
Graph as 3y=-5x+7;; y= -(5/3)x + (7/3)
That is a line.
The other line is y>4. That is a horizontal line where y=4.
The solution to this problem, assuming that both equations have to be satisfied, lies ON the line ABOVE y=4, not including the point where y=4.
graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C4%2C%28-5x%2F3%29%2B%287%2F3%29%29