SOLUTION: When a group of 50 consecutive multiples of 7 is added the answer is 12 075. (a) What is the smallest of these numbers? (b) What is the largest of these numbers?

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: When a group of 50 consecutive multiples of 7 is added the answer is 12 075. (a) What is the smallest of these numbers? (b) What is the largest of these numbers?      Log On


   



Question 977881: When a group of 50 consecutive multiples of 7 is added the answer is 12 075.
(a) What is the smallest of these numbers?
(b) What is the largest of these numbers?

Answer by Alan3354(69443) About Me  (Show Source):
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When a group of 50 consecutive multiples of 7 is added the answer is 12 075.
(a) What is the smallest of these numbers?
(b) What is the largest of these numbers?
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12075/50 = 241.5 the center
There are 25 integers below it, and 25 above it.
238 is the adjacent integer below it, 245 above it.
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238 - 7*24 = 70
245 + 7*24 = 413