SOLUTION: Solve for k LN(1/2)=5700K

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Question 977792: Solve for k
LN(1/2)=5700K
Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
LN(1/2) is the natural logarithm which is base e, therefore
LN(1/2) = -6.9314718056e-1
5700k = -6.9314718056e-1
k = -6.9314718056e-1 /5700
k = −1.216047685e−4
k = −0.000121605