Question 977729: A father is twice as old as his son. He was 6 times his son’s age 20 years ago. What
is the father’s present age? Answer by Cromlix(4381) (Show Source):
You can put this solution on YOUR website! hi there,
A father is twice as old as his son
F = 2S
He was 6 times his son’s age 20 years ago
F - 20 = 6(S - 20)
Replace F with 2S from first equation
2s - 20 = 6s - 120
Collect like terms
2s - 6s = -120 + 20
-4s = -100
s = 25
Father's present age is 50 yrs old
hope this helps:-)
