SOLUTION: Jeremy paid for his breakfast with 36 coins consisting of nickels and dimes. If the bill was$3.50 then how many of each type of coin did he use

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Jeremy paid for his breakfast with 36 coins consisting of nickels and dimes. If the bill was$3.50 then how many of each type of coin did he use       Log On


   

Question 977702: Jeremy paid for his breakfast with 36 coins consisting of nickels and dimes. If the bill was$3.50 then how many of each type of coin did he use
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
x+y=36,
0.05*x+0.1*y=3.50
x=36-y
Substitute for x
0.05*(36-y)+0.1*y=3.5
Multiply out
1.8-0.05*y+0.1*y=3.5
Combine like terms.
0.05*y=1.7
Isolate y
y=34 dimes
x=36-y
Calculate x
x=2 nickels
Check
0.05*2+0.10*34=3.50
0.10+3.40=3.50
3.5=3.5
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