SOLUTION: Given the function g=(t^(2)-3)/t, find the function that gives the gradient of the curve of the function g at any point on the curve.

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Question 977452: Given the function g=(t^(2)-3)/t, find the function that gives the gradient of the curve of the function g at any point on the curve.
Found 2 solutions by anand429, Alan3354:
Answer by anand429(138) About Me  (Show Source):
You can put this solution on YOUR website!
Gradient of g = d(g)/d(t)
=d%28%28t%5E%282%29-3%29%2Ft%29%2Fd%28t%29
=2t+-3%2A%28-2%2F%28t%5E2%29%29
=2t+%2B6%2F%28t%5E2%29

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Given the function g=(t^(2)-3)/t, find the function that gives the gradient of the curve of the function g at any point on the curve.
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g(t) = t - 3/t
It's the 1st derivative.
g'(t) = 1+%2B+3%2Ft%5E2
t <> 0