SOLUTION: Two cyclist leave from the intersection of two roads at the same time. The angle between the two roads is 82°. In one hour, one cyclist travels 18km along one road and the other tr
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Question 977449: Two cyclist leave from the intersection of two roads at the same time. The angle between the two roads is 82°. In one hour, one cyclist travels 18km along one road and the other travels 14 km along the other road. how far apart, in a direct line, are the cyclist at the end of this hour ? Found 2 solutions by Alan3354, Cromlix:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Two cyclist leave from the intersection of two roads at the same time. The angle between the two roads is 82°. In one hour, one cyclist travels 18km along one road and the other travels 14 km along the other road. how far apart, in a direct line, are the cyclist at the end of this hour ?
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Use the Cosine Law.
You can put this solution on YOUR website! Hi there,
Using the cosine rule:
Cos A = 82 degrees
b= 14 km
c = 18 km
a^2 = b^2 + c^2 - 2bc Cos A
a^2 = 14^2 + 18^2 - 2x 14 x 18 x Cos82
a^2 = 449.857
a = square root of 449.857
a = 21.2 km
This how far apart they are after an hour.
Hope this helps:-)
