SOLUTION: A coffee house has 20 pounds of a coffee that sells for $4 per pound. How many pounds of a coffee that sells for $8 per pound should be mixed with the 20 pouds of $4 per pound coff
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Question 97741: A coffee house has 20 pounds of a coffee that sells for $4 per pound. How many pounds of a coffee that sells for $8 per pound should be mixed with the 20 pouds of $4 per pound coffee to obtain a blend that will sell for $5? How much of the $5 per pound coffee is there to sell? Found 2 solutions by Nate, ankor@dixie-net.com:Answer by Nate(3500) (Show Source):
You can put this solution on YOUR website! (4(20) + 8(x))/(20 + x) = 5
80 + 8x = (20 + x)5
80 + 8x = 100 + 5x
3x = 20
x = 20/3 pounds of 8$ per pound
20 + 20/3 = 60/3 + 20/3 = 80/3 pounds in all
You can put this solution on YOUR website! A coffee house has 20 pounds of a coffee that sells for $4 per pound. How many pounds of a coffee that sells for $8 per pound should be mixed with the 20 pounds of $4 per pound coffee to obtain a blend that will sell for $5?
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Let x = amt of $8 coffee required
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It says it will be mixed with 20 lb of $4 coffee, therefore:
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Resulting amt = (x+20)
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Simple equation:
4(20) + 8x = 5(x+20)
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80 + 8x = 5x + 100
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8x - 5x = 100 - 80
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3x = 20
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x = 20/3
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x = 6 lb of $8 coffee required
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"How much of the $5 per pound coffee is there to sell?"
20 + 6 = 26 lb of $5 coffee to sell
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Check solution:
4(20) + 8(6) = 5(26)
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Using a calculator
80 + 53.3333 = 133.3333, proves our solution
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