Question 977346: The product of two consecutive integers is the square of the lesser integer minus 9. Find the greater of the two integers. Answer by Cromlix(4381) (Show Source):
You can put this solution on YOUR website! Hi there,
Make the first integer = 'x'
So two consecutive integers
=> x, x + 1
The product of the two consecutive integers
is the square of the lesser integer minus 9
=> x^2 - 9
Therefore
x(x + 1) = x^2 - 9
Multiply out left hand side
x^2 + x = x^2 - 9
Sort out like terms
x^2 - x^2 + x = x^2 - x^2 - 9
+> x = -9
This is the lesser of the two integers.
The greater will be -9 + 1 = -8
-9 x -8 = (-9)^2 - 9
=> 72 = 81 -9
=> 72 = 72
Hope this helps:-)
