SOLUTION: My question is:
Form a polynomial f(x) with real coefficients having the given degree and zeros
Degree 5; zeros: -6; -i; -3+1
Thank you
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-> SOLUTION: My question is:
Form a polynomial f(x) with real coefficients having the given degree and zeros
Degree 5; zeros: -6; -i; -3+1
Thank you
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Question 977338: My question is:
Form a polynomial f(x) with real coefficients having the given degree and zeros
Degree 5; zeros: -6; -i; -3+1
Thank you Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! The complex roots are conjugate
5 roots are -i, +i, 3-i, 3+i, and -6
(x+6)(x^2+1)
for the other, (1/2)[-b +/- sqrt (b^2-4ac)].=-6 for b and sqrt (36-40)=(1/2)(-6 +/-sqrt (-4)
That is (1/2) (-6+/-2i)=-3 +/- i
This requires -4ac=-40 or ac=10. Let a=1 and c= 10
so the last polynomial factor is x^2+6x+10
The polynomial would be (x+6)(x^2+1)(x^2+6x+10)
Multiplying it out, I get
x^5+12x^4+47x^3+72x^2+46x+60
