SOLUTION: How do you solve this problem? assuming x>0 and y>0, if 16y^2+40xy+25x^2=36, what is the value of 3(4y+5x)?

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Question 977109: How do you solve this problem?
assuming x>0 and y>0, if 16y^2+40xy+25x^2=36, what is the value of 3(4y+5x)?
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
How do you solve this problem?
assuming x>0 and y>0, if 16y^2+40xy+25x^2=36, what is the value of 3(4y+5x)?
***
16y^2+40xy+25x^2=36
(4y+5x)^2=36
4y+5x=√36=±6
3(4y+5x)=±18