SOLUTION: Given: right triangle ABC with a=2 and c=√7 find b c is the hypotenuse, a is the base, and b makes the right triangle basically; height. So, I did Cosine or SOHCAHTOA,

Algebra ->  Trigonometry-basics -> SOLUTION: Given: right triangle ABC with a=2 and c=√7 find b c is the hypotenuse, a is the base, and b makes the right triangle basically; height. So, I did Cosine or SOHCAHTOA,       Log On


   

Question 977081: Given: right triangle ABC with a=2 and c=√7 find b
c is the hypotenuse, a is the base, and b makes the right triangle basically; height.
So, I did Cosine or SOHCAHTOA, CAH. Cosine - adjacent over hypotenuse. So I did, cos(2/√7) = .99 which is equivalent to 1. But, that answer didn't pop up. And I also did the Law of Sine.
Sin(30°)/b x Sin(60°)/2
2Sin(30°) divides by Sin(60°) = 1.15
Still those two are not the answer in the multiple choice.
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
a=2
b=sqrt(3)
c=sqrt (7)
a^2+b^2=c^2
cos (2/sqrt (7)=0.7559
sqrt (7) is at least 2.6, so it can't be 0.99
cosine =40.89 degrees
sin (sqrt(3/7))=0.6547=40.89 degrees, which it should.
b must be sqrt (3)