SOLUTION: a number consists of three digit whose sum is 17 . The middle digit is one more than the sum of the other two digits. If digits are reversed, the new number is 396 less than the or
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Question 976910: a number consists of three digit whose sum is 17 . The middle digit is one more than the sum of the other two digits. If digits are reversed, the new number is 396 less than the original number. What is the number? Answer by richwmiller(17219) (Show Source):
You can put this solution on YOUR website! a+b+c=17
b=1+a+c
100a+10b+c-100c-10b-a=396
99a-99c=396
a-c=4
a=c+4
b=1+a+c
b=1+c+4+c
b=5+2c
a+b+c=17
(c+4)+[5+2c]+c=17
4c+9=17
4c=8
c=2
a=6
b=9
number is 692
check
692-296=396
ok
