SOLUTION: y = 1 - x + x^2/2! - x^3/3! + x^4/4! - ... then d^2y/dx^2 is equal to: a) -x b) -y c) x d) y
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-> SOLUTION: y = 1 - x + x^2/2! - x^3/3! + x^4/4! - ... then d^2y/dx^2 is equal to: a) -x b) -y c) x d) y
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Question 976802
:
y = 1 - x + x^2/2! - x^3/3! + x^4/4! - ... then d^2y/dx^2 is equal to:
a) -x
b) -y
c) x
d) y
Answer by
Fombitz(32388)
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y = 1 - x + x^2/2! - x^3/3! + x^4/4! - ...
dy/dx=-1+x-x^2/2!+x^3/3!- ...
d2y/dx2=1 - x + x^2/2! - x^3/3! + ...
Looks like it equals the original y.