Question 976218: In the morning, Maria drove to an appointment at 50mph. Her average speed on the return trip in the afternoon was 40 mph. The return trip took 1/10 hour longer. How far did she travel to the appointment?
Answer by jim_thompson5910(35256)   (Show Source):
You can put this solution on YOUR website! x = distance from home to appointment
Morning:
d = r*t
x = 50*t
t = x/50
It takes her x/50 hours to drive x miles in the morning at 50 mph
Afternoon:
d = r*t
x = 40*t
t = x/40
It takes her x/40 hours to drive x miles in the afternoon at 40 mph
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"The return trip took 1/10 hour longer", so that means
(return trip time) = (time to get to appointment)+(1/10 of an hour)
x/40 = (x/50) + (1/10)
x/40 = (x/50) + (1/10)*(5/5)
x/40 = (x/50) + (5/50)
x/40 = (x+5)/50
50x = 40(x+5)
50x = 40x+200
50x-40x = 200
10x = 200
x = 200/10
x = 20
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Summary:
x = 20
The distance from home to the appointment is 20 miles
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