The other tutor didn't use the substitution method but used the 
addition (elimination) method.  Even though it's easier here, one
must follow instructions.  Here's the substitution method:
solve the equation by the use of substitution method showing all the steps taken
in solving equation;
 Get rid of the fractions first by muyltiplying the first equation
through by the LCD of 10 and the second one through by the LCD of 12
Get rid of the fractions first by muyltiplying the first equation
through by the LCD of 10 and the second one through by the LCD of 12
 Solve the first equation for 4x = 20-15y
Then since 28x is 7*4x, replace 28x by 7(20-15y) in the second equation:
      28x-15y = -60
7(20-15y)-15y = -60
 140-105y-15y = -60
     140-120y = -60
        -120y = -200
            y = 5/3
Substitute in 
           4x = 20-15y
           4x = 20-15(5/3)
           4x = 20-25
           4x = -5
            x = -5/4
Edwin
Solve the first equation for 4x = 20-15y
Then since 28x is 7*4x, replace 28x by 7(20-15y) in the second equation:
      28x-15y = -60
7(20-15y)-15y = -60
 140-105y-15y = -60
     140-120y = -60
        -120y = -200
            y = 5/3
Substitute in 
           4x = 20-15y
           4x = 20-15(5/3)
           4x = 20-25
           4x = -5
            x = -5/4
Edwin