SOLUTION: If the length and breadth of a rectangle is increased by 25 and 20 percent respectively,then percentage change in perimeter?

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Question 975893: If the length and breadth of a rectangle is increased by 25 and 20 percent respectively,then percentage change in perimeter?
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
If the length and breadth of a rectangle is increased by 25 and 20 percent respectively,then percentage change in perimeter?
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P1 = 2L + 2W
--> P2 = 2(1.25L) + 2(1.2W) = 2.5L + 2.4W
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(2.5L + 2.4W) - (2L + 2W)/(2L + 2W) = (0.5L + 0.4W)/(2L + 2W)
% = 100*(0.5L + 0.4W)/(2L + 2W)
% = (50L + 40W/(2L + 2W)
% change = (25L + 20W)/(L + W)
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or
% change = 20+%2B+5L%2F%28L+%2B+W%29