Question 975628: Given log base 8 {xy} = 3, find x and y. I've found that it becomes xy = 3^8, therefore xy = 512, but after that what should I do? Thank you tutors for making time to help me!
Found 2 solutions by Alan3354, Edwin McCravy:
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! Given log base 8 {xy} = 3, find x and y. I've found that it becomes xy = 3^8, therefore xy = 512, but after that what should I do?
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x = 512/y
y = 512/x
There's nothing more that can be done.
Answer by Edwin McCravy(20066)  (Show Source):
You can put this solution on YOUR website!
Actually it's 83 not 38.
The base of the log is the base of the exponent.
log8(xy) = 3
becomes the equation
xy = 83
xy = 512 <-- so you had 512, so you must have had 83, not 38.
There are many solutions to that. There are infinitely many. Maybe
you were to find just the positive integer solutions. If so,
the solution (x,y) could be any of these:
(1,512) (2,256) (4,128) (8,64) (16,32) (32,16) (64,8) (128,4) (256,2) (512,1)
Edwin
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