SOLUTION: Can someone help me solve this problem I can not figure out how to put the exponents, so I will place them above the x 8 7 6 8x-6x + 12x ___________ __ 3 2x 8

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Can someone help me solve this problem I can not figure out how to put the exponents, so I will place them above the x 8 7 6 8x-6x + 12x ___________ __ 3 2x 8      Log On


   



Question 975585: Can someone help me solve this problem
I can not figure out how to put the exponents, so I will place them above the x
8 7 6
8x-6x + 12x
______________
3
2x
8ecponent goes with the 8, 7 exponent goes with 6, and the other 6 goes with the 12
Thank You

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Can someone help me solve this problem
I can not figure out how to put the exponents, so I will place them above the x
8 7 6
8x-6x + 12x
______________
3
2x
===================
Use ^ (Shift 6) for exponents.
(8x^8 - 6x^7 + 12x^6)/(2x^3)
-------------------
Like that.
%288x%5E8+-+6x%5E7+%2B+12x%5E6%29%2F%282x%5E3%29
==============
There's nothing to solve, tho. It's not an equation.
Step 2 is say what you want to do.
----
It can be simplified.
= 2%2A%284x%5E8+-+3x%5E7+%2B+6x%5E6%29%2F%282x%5E3%29
Cancel the 2's
= %284x%5E8+-+3x%5E7+%2B+6x%5E6%29%2Fx%5E3
= x%5E3%2A%284x%5E5+-+3x%5E4%2B+6x%5E3%29%2Fx%5E3
Cancel the x^3
= 4x%5E5+-+3x%5E4%2B+6x%5E3