SOLUTION: State the number of complex zeros, the possible number or real and imaginary zeros, and the possible rational zeros for the function. Then find all zeros
f(x)= x^3+1
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f(x)= x^3+1
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Question 975579: State the number of complex zeros, the possible number or real and imaginary zeros, and the possible rational zeros for the function. Then find all zeros
f(x)= x^3+1 Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! x^3+1=0
This has 3 possible zeros. If there are any complex zeros, there can only be 1 rational root, since the complex zeros are conjugate. If there are two rational zeros, they have to be the same.
(x+1) (x^2-x+1)=0, factoring a sum of cubes.
There is 1 rational root, , -1
There are two complex roots
x=(1/2) 1 +./- sqrt (1-4)= (1/2)+/- (1/2) * i * (sqrt 3)
