SOLUTION: In a party 70% of the guest drink coffee, 65% of the guest drink Tea, 27% of guest didnt drink anything and 248 guests drink both tea and coffee. How much guests came for the party

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: In a party 70% of the guest drink coffee, 65% of the guest drink Tea, 27% of guest didnt drink anything and 248 guests drink both tea and coffee. How much guests came for the party      Log On


   



Question 975322: In a party 70% of the guest drink coffee, 65% of the guest drink Tea, 27% of guest didnt drink anything and 248 guests drink both tea and coffee. How much guests came for the party?
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
I am assuming that coffee and tea were the only beverages being served.
Otherwise, we cannot solve the problem.

If 27% of the guests didn't drink anything, then
100% - 27% = 73% drank either coffee or tea, or both.
Since 70% drank coffee, 73% - 70% = 3% must have drunk only tea.
The other 65% - 3% = 62% of the tea-drinking guests drank both beverages (coffee and tea).
x= number of guests that came for the party
%2262%25%22=62%2F100=0.62 of those x guests is 0.62x
0.62x=248--->x=248%2F0.62--->highlight%28x=400%29 .
So, highlight%28400%29 guests came for the party.

CHECKING:
Of those 400 guests, 27%, or 0.27%2A400=108 , drank nothing;
70%, or 0.70%2A400=280 , drank coffee,
and 65%, or 0.65%2A400=260 , drank tea.
If we add all those numbers up, we get
108%2B280%2B260=648 .
Since there were 400 guests, that means that
648-400=248 guests were counted twice,
and that is because they drank both: tea and coffee.