SOLUTION: find the center and radius of the circle (X+3)^2+(y+2)^2=4 Center= radius= Show the equation that represents the circle by rewriting it in standard form and find the center and

Algebra ->  Graphs -> SOLUTION: find the center and radius of the circle (X+3)^2+(y+2)^2=4 Center= radius= Show the equation that represents the circle by rewriting it in standard form and find the center and      Log On


   



Question 975281: find the center and radius of the circle
(X+3)^2+(y+2)^2=4
Center=
radius=
Show the equation that represents the circle by rewriting it in standard form and find the center and radius of the circle
x^2+y^2-4x+4y+7=0

Answer by josgarithmetic(39627) About Me  (Show Source):
You can put this solution on YOUR website!
Answer for the first part can be based directly on knowing how to use standard form equation of a circle.
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Center is (-3,-2)
Radius is 2.

The second question you can answer using Completing the Square and simple algebra.
The term for the x's is 4 and the term for the y's is also 4.
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This is all I am showing for this part:
%28x-2%29%5E2%2B%28y%2B2%29%5E2=1