Question 975182: A study comparing attitudes toward death was conducted in which organ donors (individuals who had signed organ donor cards) were compared with nondonors. Templer's Death Anxiety Scale (DAS) was administered to both groups. On this scale, high scores indicate high anxiety concerning death. The results were reported as follows.
.................n Mean Std.Dev.
Organ Donors 28.. 5.75.. 2.76
Nonorgan Donors 69.. 7.82.. 3.45
Construct the 95% confidence interval for the difference between the means, μnon − μdonor. (Estimate df by using the smaller value of dfdonor and dfnon.)
lower limit: ?
upper limit: ?
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! t=[(x1-x2)-(mu1-mu2)]/ sqrt {(s1^2)/n1) +(s2^2)/n2)}
I get a t-value of -3.1, which from the table at 26 df has a p-value between 0.005 and 0.025 (calculator 0.023).
I get a SE of 0.666
t value *SE= +/-2.056*(0.666)=1.37
CI is -2.07 +/- 1.37 difference in means +/- tSE
95% CI = (-3.44,-0.70)
The CI does not contain zero; therefore, there is a significant difference between these means at the p=0.05 level.
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