SOLUTION: Suppose f(x)=x^2 over the domain of f, then: (A)f^(-1) (x)=√x (B)f^(-1) (x)=x/2 (C)f^(-1) (x)=-x^2 (D)f^(-1) (x) does n

Algebra ->  Functions -> SOLUTION: Suppose f(x)=x^2 over the domain of f, then: (A)f^(-1) (x)=√x (B)f^(-1) (x)=x/2 (C)f^(-1) (x)=-x^2 (D)f^(-1) (x) does n      Log On


   

Question 975181: Suppose f(x)=x^2 over the domain of f, then:
(A)f^(-1) (x)=√x
(B)f^(-1) (x)=x/2
(C)f^(-1) (x)=-x^2
(D)f^(-1) (x) does not exist
(E) none of the above
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

if f%28x%29=x%5E2, then inverse f%5E%28-1%29%28x%29 will be:
f%28x%29=x%5E2.......recall that f%28x%29=y, so we have
y=x%5E2...........swap x and y
x=y%5E2.......solve for y
y=+sqrt%28x%29, your inverse f%5E%28-1%29%28x%29
f%5E%28-1%29%28x%29+=+sqrt%28x%29

so, your answer is: (A) f%5E%28-1%29%28x%29+=+sqrt%28x%29