SOLUTION: a car traveling with 5/7 of its acual speed covers 42 km in 1 hr 40 min48 sec.what is the actual speed of the car?

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Question 975161: a car traveling with 5/7 of its acual speed covers 42 km in 1 hr 40 min48 sec.what is the actual speed of the car?
Found 2 solutions by josmiceli, MathLover1:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +s+ = actual speed in km/hr
------------------------------
Convert time to hrs
+40%2F60+=+.6667+ hrs
+48%2F3600+=+.01333+ hrs
+1+%2B+.6667+%2B+.01333+=+1.68+ hrs
+42+=+%28%28+5%2F7+%29%2As+%29%2A+1.68+
+7%2A42+=+5s%2A1.68+
+294+=+8.4s+
+s+=+35+
The actual speed is 35 km/hr
----------------
check:
+%28+5%2F7+%29%2A35+=+25+ km/hr
+42+=+%28%28+5%2F7+%29%2As+%29%2A+1.68+
+42+=+25%2A+1.68+
+1.68+=+1.68+
OK

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

let actual speed be s
if a car traveling with 5%2F7 of its actual speed,we have %285%2F7%29s
if a car covers a distance d=42km in a time t=1h+40min48s, then we have
d=s%2At
42km=%285%2F7%29s%2At
....convert time to hours:
1h++=+1h
40min+=+40%2F60+=+%282%2F3%29h
48s+=+48%2F3600+=+%281%2F75%29+h
Therefore, 1 hr 40 min 48 sec = 1 + 2/3 + 1/75 hour = 126/75 hour
t=1h+40min48s=%281+%2B+2%2F3+%2B+1%2F75+%29h+=+%28126%2F75%29+h=1.68h
42km=%285%2F7%29s%2A1.68h
42km%2F1.68h=%285%2F7%29s
4200km%2F168h=%285%2F7%29s
25%28km%2Fh%29=%285%2F7%29s
%287%2A25%2F5%29%28km%2Fh%29=s
%287%2Across%2825%295%2Fcross%285%291%29%28km%2Fh%29=s
%287%2A5%29%28km%2Fh%29=s
s=35%28km%2Fh%29