SOLUTION: (5x^0y^-7/2x^-2y^4)^-2

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Question 975102: (5x^0y^-7/2x^-2y^4)^-2
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
(5x^0y^-7/2x^-2y^4)^-2;;; 5x^0=1 ;;;y^(-7/2)*(-2)=y^7;;;; (-2)^-2=(1/(-2)^2) or (1/4);;;(y^4)^-2=y^-8
1* y^7*(1/4)y^-8
y^7/(1/4)y^8
(4/y)